【答案】
分析:當(dāng)n=1時(shí),y=x
2-
x+
,設(shè)y=x
2-
x+
=0的兩根式a,b,則a+b=
,ab=
,A
1B
1=
=1-
,同法求出當(dāng)n=2時(shí),A
2B
2=
=
-
,當(dāng)n=3 時(shí),A
3B
3=
=
-
,當(dāng)n=2011 時(shí),A
2011B
2011=
×
=
-
,相加即可求出答案.
解答:解:當(dāng)n=1時(shí),y=x
2-
x+
,設(shè)y=x
2-
x+
=0的兩根式a,b,
則a+b=
,ab=
,A
1B
1=
=
=
=1-
,
當(dāng)n=2時(shí),y=x
2-
x+
,同法可求出:A
2B
2=
=
-
,
當(dāng)n=3 時(shí),y=x
2-
x+
,同法可求出:A
3B
3=
=
-
,
…
當(dāng)n=2011 時(shí),y=x
2-
x+
×
,同法可求出:A
2011B
2011=
×
=
-
,
∴|A
1B
1|+|A
2B
2|+…+|A
2011B
2011|的值為1-
+
-
+
-
+…+
-
=1-
=
,
故選D.
點(diǎn)評:本題主要考查對拋物線與X軸的交點(diǎn),根與系數(shù)的關(guān)系,完全平方公式等知識點(diǎn)的理解和掌握,能根據(jù)所得的數(shù)據(jù)找出規(guī)律是解此題的關(guān)鍵.