11. . 乙 (2) . 查看更多

 

題目列表(包括答案和解析)

一、本題共10小題,每小題5分.每小題給出的四個選項中,有的小題只有一個選項正確,有的小題有多個選項正確,全部選對得5分,選不全得3分,有選錯或不答得0分.

題號

1

2

3

4

5

6

7

8

9

10

答案

AB

D

B

D

AC

C

A

D

B

BCD

學(xué)科網(wǎng)(Zxxk.Com)二、本題共2小題,共18分

  11(4分)偏小

12.(8分)(1)電路圖(4分)

 

 

(2)9.0,10.0 (每空2分)

 

13.(4分)右  (2分)          t=  (2分)

14、(13分)解:(1)飛船在運行過程中萬有引力提供向心力

 

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      • 2分)

         

         

         

         

         

         

         

         

         

         

         

         

         

         

         

         

         

        由(2) (3)得:飛船運行周期:

        2分)

         

         

         

         

         

         

         

        學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com),學(xué)科網(wǎng)(Zxxk.Com) 

         

         

         

         

         

         

         

         

         

         

         

         

         

         

         

         

         

         

         

         

         

        15.(13分)解(1)如圖所示,帶電質(zhì)點在重力mg(大小及方向均已知)、洛倫茲力qv0B(方向已知)、電場力qE(大小及方向均未知)的作用做勻速直線運動。根據(jù)力三角形知識分析可知:當(dāng)電場力方向與磁場方向相同時,場強有最小值。

        學(xué)科網(wǎng)(Zxxk.Com)根據(jù)物體的平衡規(guī)律有

                             (1分)

                             (1分)

        解得                     (2分)

                                  (2分)

        (2)當(dāng)電場力和重力平衡時,帶點質(zhì)點才能只受洛倫茲力作用做勻速圓周運動

        則有:                 (1分)

        得:                   (1分)

        要使帶電質(zhì)點經(jīng)過x軸,圓周的直徑為   (2分)

        根據(jù)(1分)

                                   (2分)

        16.(12分)解:⑴小球做勻速圓周運動,突然放繩則小球以原有的速度做勻速直線運動到C,在C點處一瞬間8m繩突然拉直,沿繩方向的速度vyP突變?yōu)?,而小球?qū)⒁詖x做勻速圓周運動,到達B點,

        學(xué)科網(wǎng)(Zxxk.Com)由幾何關(guān)系可知:S1=AC=   (1分)

        ∠AOC=60°=π/3

             (2分)                      

        ∠BOC=120°=2π/3     (1分)

        在C點,由矢量三角形可知:vx=vcos60°=v/2    (1分)

            (2分)

         (2分)

        學(xué)科網(wǎng)(Zxxk.Com)(2)在B點,則有:    (3分)

          解:(1)小物塊沿斜面下滑的過程中受力情況如圖所示

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