由, 所以|AF|=6, 即得|yM-yN|= 查看更多

 

題目列表(包括答案和解析)

已知點(diǎn)F(0,1),點(diǎn)P在x軸上運(yùn)動(dòng),M點(diǎn)在y軸上,N為動(dòng)點(diǎn),且滿(mǎn)足
PM
PF
=0
,
PN
+
PM
=0

(1)求動(dòng)點(diǎn)N的軌跡C方程;
(2)由直線(xiàn)y=-1上一點(diǎn)Q向曲線(xiàn)C引兩條切線(xiàn),切點(diǎn)分別為A,B,求證:AQ⊥BQ.

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已知點(diǎn)F(0,1),點(diǎn)P在x軸上運(yùn)動(dòng),M點(diǎn)在y軸上,N為動(dòng)點(diǎn),且滿(mǎn)足,
(1)求動(dòng)點(diǎn)N的軌跡C方程;
(2)由直線(xiàn)y=-1上一點(diǎn)Q向曲線(xiàn)C引兩條切線(xiàn),切點(diǎn)分別為A,B,求證:AQ⊥BQ.

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已知點(diǎn)F(0,1),點(diǎn)P在x軸上運(yùn)動(dòng),M點(diǎn)在y軸上,N為動(dòng)點(diǎn),且滿(mǎn)足數(shù)學(xué)公式,數(shù)學(xué)公式
(1)求動(dòng)點(diǎn)N的軌跡C方程;
(2)由直線(xiàn)y=-1上一點(diǎn)Q向曲線(xiàn)C引兩條切線(xiàn),切點(diǎn)分別為A,B,求證:AQ⊥BQ.

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已知點(diǎn)F(0,1),點(diǎn)P在x軸上運(yùn)動(dòng),M點(diǎn)在y軸上,N為動(dòng)點(diǎn),且滿(mǎn)足,
(1)求動(dòng)點(diǎn)N的軌跡C方程;
(2)由直線(xiàn)y=-1上一點(diǎn)Q向曲線(xiàn)C引兩條切線(xiàn),切點(diǎn)分別為A,B,求證:AQ⊥BQ.

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已知點(diǎn)F(0,1),點(diǎn)P在x軸上運(yùn)動(dòng),M點(diǎn)在y軸上,N為動(dòng)點(diǎn),且滿(mǎn)足
(1)求動(dòng)點(diǎn)N的軌跡C方程;
(2)由直線(xiàn)y=-1上一點(diǎn)Q向曲線(xiàn)C引兩條切線(xiàn),切點(diǎn)分別為A,B,求證:AQ⊥BQ.

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