Question

14．甲乙兩倉(cāng)共存糧2400噸，甲倉(cāng)調(diào)出$\frac{1}{6}$，放入乙倉(cāng)后乙倉(cāng)存糧比甲倉(cāng)少$\frac{2}{5}$，兩倉(cāng)原來各存糧多少噸？

Answer 1

分析 設(shè)甲倉(cāng)原來存糧x噸，則乙倉(cāng)原來存糧2400-x噸，根據(jù)等量關(guān)系：甲倉(cāng)調(diào)出$\frac{1}{6}$剩下的×（1-$\frac{2}{5}$）=乙倉(cāng)原來存糧+甲倉(cāng)調(diào)出得$\frac{1}{6}$，列方程解答即可得甲倉(cāng)原來存糧，再求乙倉(cāng)原來存糧即可．

解答 解：設(shè)甲倉(cāng)原來存糧x噸，則乙倉(cāng)原來存糧2400-x噸，
（1-$\frac{1}{6}$）×（1-$\frac{2}{5}$）x=2400-x+$\frac{1}{6}$x
           $\frac{5}{6}×\frac{3}{5}$x=2400-$\frac{5}{6}$x
               $\frac{4}{3}$x=2400
                 x=1800
2400-1800=600（噸）
答：甲倉(cāng)原來存糧1800噸，則乙倉(cāng)原來存糧600噸．

點(diǎn)評(píng) 本題考查了分?jǐn)?shù)四則復(fù)合應(yīng)用題，關(guān)鍵是根據(jù)等量關(guān)系：甲倉(cāng)調(diào)出$\frac{1}{6}$剩下的×（1-$\frac{2}{5}$）=乙倉(cāng)原來存糧+甲倉(cāng)調(diào)出得$\frac{1}{6}$，列方程．