解:(1)

=(15+1)×

,
=16×

,
=10;
(2)

=2-

×

-

,
=2-1

-

,
=2-(1

+

),
=2-2,
=0;
(3)(

)×12
=

×12+

×12-

×12,
=6+4-3,
=7.
分析:算式(1)(3)可根據(jù)乘法分配律進(jìn)行計(jì)算;
算式(2)可根據(jù)一個(gè)數(shù)減兩個(gè)數(shù),等于減去這兩個(gè)數(shù)的和的減法性質(zhì)進(jìn)行計(jì)算.
點(diǎn)評(píng):完成本題要認(rèn)真分析式中數(shù)據(jù)的特點(diǎn),然后運(yùn)用合適的方法進(jìn)行計(jì)算.