(2004?廈門)遞等式計算.
1224÷36×25-758 132.5-18÷7.5+7.6 12-
2
7
+
1
7
÷
1
5
[
3
4
-(
7
16
-
1
4
)]×
8
9
分析:(1)先算除法,再算乘法,最后算減法;
(2)先算除法,再算減法,最后算加法;
(3)先算除法,再算減法,最后算加法;
(4)先算小括號里面的減法,再算中括號里面的減法,最后算乘法.
解答:解:(1)1224÷36×25-758,
=34×25-758,
=850-758,
=92;

(2)132.5-18÷7.5+7.6,
=132.5-2.4+7.6,
=130.1+7.6,
=137.7;

(3)12-
2
7
+
1
7
÷
1
5

=12-
2
7
+
5
7
,
=11
5
7
+
5
7
,
=12
3
7


(4)[
3
4
-(
7
16
-
1
4
)]×
8
9

=[
3
4
-
3
16
8
9
,
=
9
16
×
8
9
,
=
1
2
點評:根據(jù)題意,先找請運算順序,然后再進一步計算,能簡算的要簡算.
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