分析:(1)可將101拆分為100+1后根據(jù)乘法分配律計算;
(2)可將32拆分為4×8后,根據(jù)乘法結(jié)合律計算;
(3)根據(jù)四則混合運算的運算順序計算即可:先算乘除,再算加減,有括號的要先算括號里面的.
(4)可根據(jù)一個數(shù)除以兩個數(shù)的積,等于用這個數(shù)分別除以這兩個數(shù)的除法性質(zhì)及乘法交換律計算.
解答:解:(1)2.65×101
=2.65×(100+1),
=2.65×100+2.65×1,
=265+2.65,
=267.65;
(2)0.25×32×1.25
=(0.25×4)×(8×1.25),
=1×10,
=10;
(3)40-(7.7-480%÷1.2)
=40-(7.7-4.8÷1.2),
=40-(7.7-4),
=40-3.7,
=36.3;
(4)
÷[(0.2+
)×0.375].
=
÷[(
+
)×
],
=
÷÷(
+
),
=1÷
,
=
.
點評:當(dāng)算式中同時含有分?jǐn)?shù)、小數(shù)、或百分?jǐn)?shù)時,應(yīng)根據(jù)式中數(shù)據(jù)的特點將它們靈活互化后再進(jìn)行計算.