分析:(1)101×67把101拆成(100+1)×67,再利用乘法的分配律變成100×67+1×67計算簡便;
(2)98.5-42.28-7.72利用一個數(shù)連續(xù)減去兩個數(shù)等于這個數(shù)減去這兩個數(shù)的和變成98.5-(42.28+7.72)計算簡便;
(3)1.38+14.7+8.62+5.3利用加法的交換律和結(jié)合律變成(1.38+8.62)+(14.7+5.3)計算簡便;
(4)3200÷4÷25利用一個數(shù)連續(xù)除以兩個數(shù)等于這個數(shù)除以這兩個數(shù)的積變成3200÷(25×4)計算簡便.
解答:解:(1)101×67,
=(100+1)×67,
=100×67+1×67,
=6700+67,
=6767;
(2)98.5-42.28-7.72,
=98.5-(42.28+7.72),
=98.5-50,
=48.5;
(3)1.38+14.7+8.62+5.3,
=(1.38+8.62)+(14.7+5.3),
=10+20,
=30;
(4)3200÷4÷25,
=3200÷(25×4),
=3200÷100,
=32.
點評:完成本題要注意分析式中數(shù)據(jù),運用合適的簡便方法計算.