1×2+2×3+…+19×20.
分析:此題利用拆分的方法進(jìn)行解答,首先知道下列公式:n×(n+1)=n×n+n,12+22+…+n2=n×(n+1)×(2n+1)÷6,因?yàn)?×2+2×3+3×4+4×5+…+19×20=(12+22…+192)+(1+2+3…+19),所以用以上關(guān)系式和求和公式簡(jiǎn)算即可.
解答:解:1×2+2×3+…+19×20,
=(12+22+…+192)+(1+2+…+19),
=19×(19+1)×(2×19+1)÷6+(1+19)×19÷2,
=19×20×39÷6+20×19÷2,
=2470+190,
=2660.
點(diǎn)評(píng):此題考查了學(xué)生審題與利用公式簡(jiǎn)算的能力,以及對(duì)數(shù)進(jìn)行拆分的方法.
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