Question

將mg溶質(zhì)質(zhì)量分?jǐn)?shù)為a%的稀H₂SO₄與ng溶質(zhì)質(zhì)量分?jǐn)?shù)為b%的稀H₂SO₄混合，則混合后的溶液中硫酸的質(zhì)量分?jǐn)?shù)是

 

．

Answer 1

考點(diǎn)：有關(guān)溶質(zhì)質(zhì)量分?jǐn)?shù)的簡單計(jì)算

專題：溶液的組成及溶質(zhì)質(zhì)量分?jǐn)?shù)的計(jì)算

分析：同種溶質(zhì)的兩溶液混合，混合后溶液中溶質(zhì)質(zhì)量分?jǐn)?shù)=

混合后溶液中溶質(zhì)質(zhì)量

混合后溶液質(zhì)量

×100%，混合溶液的質(zhì)量為混合前兩溶液的質(zhì)量和，其中溶質(zhì)質(zhì)量為混合前兩溶液中溶質(zhì)質(zhì)量和；

解答：解：因?yàn)榛旌先芤旱馁|(zhì)量為混合前兩溶液的質(zhì)量和，其中溶質(zhì)質(zhì)量為混合前兩溶液中溶質(zhì)質(zhì)量和，故混合后的溶液中H₂SO₄的質(zhì)量分?jǐn)?shù)=

ma%+nb%

m+n

×100%．
故答案為：

ma%+nb%

m+n

×100%．

點(diǎn)評(píng)：同種溶質(zhì)的不同溶液混合，混合溶液中溶質(zhì)質(zhì)量為混合前兩溶液中溶質(zhì)質(zhì)量和、溶液質(zhì)量為混合前兩溶液的質(zhì)量和，據(jù)此，計(jì)算混合溶液的溶質(zhì)質(zhì)量分?jǐn)?shù)．